Вывод изображения в форме
Вывод изображения поверх другого изображения
Привет, как правильнее сделать такую манипуляцию нужно на картинке вывести справа вверху КРАСНЫЙ.
Вывод изображения с БД и размер изображения
<div <?php $query = mysql_query("SELECT * FROM table_photos" ,$link); $array =.
Изображения на форме
Помогите пожалуйста решить задачу! Разработать приложение, позволяющее изображать на форме.
Отображение изображения в форме
Доброго дня. Существует задание, по выводу нарисованного в Paint’е изображения в форме. Имеется.
Загрузка и отображение картинки в Windows Forms c C#
В данном примере я покажу Вам как можно загрузить картинку из Интернета и отобразить ее в пользовательском интерфейсе. Изображение будет отображаться при нажатии на кнопку причем, каждый раз будет новое изображение.
Интерфейс MainForm.Designer.cs
namespace ShowImagwFromInternetWinForm
<
partial class MainForm
<
/// <summary>
/// Required designer variable.
/// </summary>
private System.ComponentModel.IContainer components = null;
/// <summary>
/// Clean up any resources being used.
/// </summary>
/// <param name="disposing">true if managed resources should be disposed; otherwise, false.</param>
protected override void Dispose(bool disposing)
<
if (disposing && (components != null))
<
components.Dispose();
>
base.Dispose(disposing);
>
#region Windows Form Designer generated code
/// <summary>
/// Required method for Designer support — do not modify
/// the contents of this method with the code editor.
/// </summary>
private void InitializeComponent()
<
this.ImagePictureBox = new System.Windows.Forms.PictureBox();
this.DownloadImageButton = new System.Windows.Forms.Button();
((System.ComponentModel.ISupportInitialize)(this.ImagePictureBox)).BeginInit();
this.SuspendLayout();
//
// ImagePictureBox
//
this.ImagePictureBox.Anchor = ((System.Windows.Forms.AnchorStyles)((((System.Windows.Forms.AnchorStyles.Top | System.Windows.Forms.AnchorStyles.Bottom)
| System.Windows.Forms.AnchorStyles.Left)
| System.Windows.Forms.AnchorStyles.Right)));
this.ImagePictureBox.BackColor = System.Drawing.SystemColors.ActiveCaption;
this.ImagePictureBox.Location = new System.Drawing.Point(12, 12);
this.ImagePictureBox.Name = "ImagePictureBox";
this.ImagePictureBox.Size = new System.Drawing.Size(435, 462);
this.ImagePictureBox.SizeMode = System.Windows.Forms.PictureBoxSizeMode.StretchImage;
this.ImagePictureBox.TabIndex = 0;
this.ImagePictureBox.TabStop = false;
//
// DonwloadImageButton
//
this.DownloadImageButton.Anchor = ((System.Windows.Forms.AnchorStyles)(((System.Windows.Forms.AnchorStyles.Bottom | System.Windows.Forms.AnchorStyles.Left)
| System.Windows.Forms.AnchorStyles.Right)));
this.DownloadImageButton.Cursor = System.Windows.Forms.Cursors.Hand;
this.DownloadImageButton.Location = new System.Drawing.Point(12, 496);
this.DownloadImageButton.Name = "DonwloadImageButton";
this.DownloadImageButton.Size = new System.Drawing.Size(435, 49);
this.DownloadImageButton.TabIndex = 1;
this.DownloadImageButton.Text = "Загрузить";
this.DownloadImageButton.UseVisualStyleBackColor = true;
this.DownloadImageButton.Click += new System.EventHandler(this.DonwloadImageButton_Click);
//
// Form1
//
this.AutoScaleDimensions = new System.Drawing.SizeF(8F, 19F);
this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font;
this.ClientSize = new System.Drawing.Size(459, 557);
this.Controls.Add(this.DownloadImageButton);
this.Controls.Add(this.ImagePictureBox);
this.Name = "Form1";
this.StartPosition = System.Windows.Forms.FormStartPosition.CenterScreen;
this.Text = "Главное окно";
((System.ComponentModel.ISupportInitialize)(this.ImagePictureBox)).EndInit();
this.ResumeLayout(false);
private PictureBox ImagePictureBox;
private Button DownloadImageButton;
>
>
Код формы с логикой программы
namespace ShowImagwFromInternetWinForm
<
public partial class MainForm : Form
<
public MainForm()
<
InitializeComponent();
>
/**
* Загружает изображение
* и возвращает его как массив байт
*
*/
private static byte[] DownloadImage(string url)
<
using var httpClient = new HttpClient();
var response = httpClient.GetByteArrayAsync(url).Result;
/**
*
* Обработчик нажатия кнопки загрзки
*
*/
private void DonwloadImageButton_Click(object sender, EventArgs e)
<
DownloadImageButton.Text = "Картинка загружается. ";
// вызываем загрузку внутри отдельной задачи, чтобы не блокировать интерфейс
Task.Run(() =>
<
// загружаем картинку
var imageBytes = DownloadImage("https://source.unsplash.com/random");
// создаем объект Bitmap из массива байт
var bitmap = new Bitmap(new MemoryStream(imageBytes));
// Устанавливаем изображение для отображение пользователю
ImagePictureBox.Image = bitmap;
Таким образом, при запуске этой программы Вы увидите пустое окно, в которое при нажатии на кнопку будет загружено изображение.
Копирование материалов разрешается только с указанием автора (Михаил Русаков) и индексируемой прямой ссылкой на сайт (http://myrusakov.ru)!
Добавляйтесь ко мне в друзья ВКонтакте: http://vk.com/myrusakov.
Если Вы хотите дать оценку мне и моей работе, то напишите её в моей группе: http://vk.com/rusakovmy.
Если Вы не хотите пропустить новые материалы на сайте,
то Вы можете подписаться на обновления: Подписаться на обновления
Если у Вас остались какие-либо вопросы, либо у Вас есть желание высказаться по поводу этой статьи, то Вы можете оставить свой комментарий внизу страницы.
Порекомендуйте эту статью друзьям:
Если Вам понравился сайт, то разместите ссылку на него (у себя на сайте, на форуме, в контакте):
Она выглядит вот так:
Комментарии ( 0 ):
Для добавления комментариев надо войти в систему.
Если Вы ещё не зарегистрированы на сайте, то сначала зарегистрируйтесь.
Display an image into windows forms
I wanted to display an image to the windows forms, but i already did this and the image did not come out.
Where did I go wrong?
Here is the code:
4 Answers 4
-
Like you are doing.
Using ImageLocation property of the PictureBox like:
Using an image from the web like:
And please, be sure that «../SamuderaJayaMotor.png» is the correct path of the image that you are using.
There could be many reasons for this. A few that come up quickly to my mind:
- Did you call this routine AFTER InitializeComponent() ?
- Is the path syntax you are using correct? Does it work if you try it in the debugger? Try using backslash (\) instead of Slash (/) and see.
- This may be due to side-effects of some other code in your form. Try using the same code in a blank Form (with just the constructor and this function) and check.
I display images in windows forms when I put it in Load event like this:
-
The Overflow Blog
Linked
Related
Hot Network Questions
Subscribe to RSS
To subscribe to this RSS feed, copy and paste this URL into your RSS reader.
Site design / logo © 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA . rev 2023.8.9.43572
By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.
Programming Examples
Are you a Programmer or Application Developer or a DBA? Take a cup of coffee, sit back and spend few minutes here 🙂
C# PictureBox Control and Image Load Progress
Table of Contents
1. Introduction to PictureBox Control and ProgressBar Control
In this article we will explore the PictureBox Control and ProgressBar Control with an example walk through. PictureBox control is mainly used for an image. Using this control, one can show standard images files in a C# windows form. The image type can be BMP, JPG, JIF, PNG, etc. A ProgressBar control shows the progress of long-running process.
We will walk through an example and explore the control properties, methods and events. The below youtube video explains the basics of PictureBox and ProgressBar controls:
2. The PictureBox Control Example
The screenshot of the application that we will create in this article is shown below:
C# PictureBox and Progress bar Example – Form Design
In the above screenshot, the PictureBox Control shows the Image after the form is loaded. Below this Control, we will see a set of LinkLable Controls, which changes the SizeMode Property of the PictureBox when a Clicks it. In the right-side Group, we will try to load the Image to the PictureBox at run-time both from your local PC and from the remote PC (Internet URL). Loading the Image from a remote machine requires internet access.
The radio buttons control how the PictureBox Control loads the image in it. In Asynchronous Mode, a thread takes care of loading an image from the Internet or even from the local machine. If the image in the Internet is of huge size and load process does not block the user interface. For a test when the Asynchronous option is selected, we can try moving the window while the image is loading.
We use the progress bar in the above application to show the progress of loading the image. The Label Control (Not visible above) next to the progress bar shows the percentage of completed image load. Now, we will start with this example.
3. Form Design of The Example
3.1 Start a C# Project
Follow the instruction below to create the startup application.
- Open the application available for download for a reference. The link is there at the end of this article. We will call this as Reference Application.
- Create a new Visual C# Windows Application using visual studio 2005 or Later.
- Place all the required control discussed in the previous section.
- First set the properties for the PictureBox Control. We can do that by checking the property for the PictureBox Control on our solution opened in the first step. Check for the Bold Font property values in the Reference Application and those are all the properties we need to change in our Application.
3.2 Set an Image to PictureBox Control
Let us see frequently used properties of the PictureBox Control before we move on to the next step. If we click the Image Property ‘…’ button C# displays a Select Resource Dialog (Refer the below Picture).
From the displayed dialog, we must select the Resource File option and click the Import Button. Now, we can pick any image in our computer system which we want to add it as a Resource. During the Form load event at run-time, we will use this image as a Resource. Once we selected the image click OK to this dialog. The below picture shows the dialog before clicking OK button below:
3.3 Embedded Image Resource
In the explorer window, we can see the picture loaded as a resource. This is shown below as sunset.jpg:
Image Resource In Explorer Pane
Now, we mark this Image as ‘Embedded Resource’. Once we make a resource as Embedded Resource, we no need to copy the image file to a physical location of the end user machine. But, note that the file should exist on our build and packaging machine. The below steps show the properties required for our example.
- Right click the loaded resource (In our case it is Sunset.jpg) and select properties.
- Select Embedded Resource as value for the ‘Build Action‘ Property.
- Nothing special with the LinkLabel Control. We can easily set it using the reference application.
- Same holds true for Groupbox, Radiobutton and the button controls.
- For ProgressBar Control, we accepted all the default values.
- Do not forget to add a label control next to the Progress Bar, as it is not shown in the Preview section.
We completed our form design. Cross check the control names from the Reference Application before we move to the coding. You can also watch the below youtube video to know how the form was designed:
4. Start Coding the Example
4.1 SizeMode Property of PictureBox Control
For all the LinkLabel Control, we provide a handler for the LinkClicked Event. Inside the handler we are going to the set the ‘SizeMode Property’ to a constant value from the ‘PictureBoxSizeMode Enumeration’. Below is the code for the entire LinkLabel handlers: